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What volume of carbon dioxide, measured at 25 °C and 741 torr, can be obtained by the reaction of 50.0 g of CaCO3 with 750 mL of 2.00M HCl solution?CaCO3(s) + HCl(aq) => CaCl2(aq) + CO2(g) + H2O(l) (unbalanced)
a.
11.2 L
b.
12.5 L
c.
18.8 L
d.
9.4 L
e.
6.25 L


Sagot :

The volume of carbon dioxide measured at 25 °C and 741 torr is 12.5L.

How is volume related to temperature?

The Charles' law concept was later updated by Joseph Gay-Lussac and generalized in 1802. At extremely high temperatures and low pressures, gases adhere to Charles' law. It can be obtained from the kinetic theory of gases under the assumption of an ideal gas and is a specific case of the general gas law.

The volume of a fixed mass of gas is linearly proportional to temperature at constant pressure.

"The volume of a fixed mass of a gas reduces when it is cooled and rises when the temperature is raised. The volume of the gas rises by 1/273 of its initial volume at 0 °C for every degree of temperature rise. Let Vo and Vt represent the gas's volumes at 0 C and t C, respectively.

The balanced equation is :

CaCO3(s) + 2HCl(aq) => CaCl2(aq) + CO2(g) + H2O(l)

50 g of CaCO3 × 1mole/100.1 g × 1 mol CO2 / 1 mol CaCO3 = 0.50 mol CO2

2.00 M HCl × 0.750 L/ 1mol × 1 mol CO2 / 2 mol HCl = 0.75 mol CO2

CaCO3 is the limiting reagent.

So, 0.50 mol CO2 will be produced.

V = 0.50 × 0.0821 L atm mol -1 K -1 ×(25+273) / 741 torr ×{ 1 atm /760 torr}

Volume = 12.5 L

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