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[tex]\displaystyle\\\begin{cases} \dfrac{1}{x} +\dfrac{1}{y+z} =\dfrac{1}{2} \\ \\ \dfrac{1}{y} +\dfrac{1}{x+z} =\dfrac{1}{3} \\ \\ \dfrac{1}{z} +\dfrac{1}{x+y} =\dfrac{1}{4} \end{cases}[/tex]

Texdisplaystylebegincases Dfrac1x Dfrac1yz Dfrac12 Dfrac1y Dfrac1xz Dfrac13 Dfrac1z Dfrac1xy Dfrac14 Endcasestex class=

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