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Sagot :
The oxidation number of Cu, C and O in CuCO₃ is, (+2), (+4) and (-2), The oxidation number of C and H in CH₄ is (-4) and (+1). The oxidation number of I and F in IF is, (+1) and (-1). The oxidation number of C, H and Cl in CH₂Cl₂ is, (0), (+1) and (-1).The oxidation number of S, and O in SO₂ is, (+4) and (-2). and for (NH₄)₂CrO₄, N has an oxidation number of -3, O has an oxidation number of -2, and Cr has an oxidation number of +6 in the compound (NH₄)₂CrO₄. The H in(NH₄)₂CrO₄ has an oxidation number of 1.
How does oxidation number work?
The number of electrons that a specific atom or ion has either gained or lost in comparison to a neutral atom is known as the oxidation number. The oxidation number of a free element is always zero. Since the compound loses electrons when it is oxidized, the meaning was enlarged to include further reactions in which electrons are lost, regardless of the presence of oxygen.
A free element's oxidation number is always zero.
A monatomic ion's charge and oxidation number are the same.
Hydrogen (H) has an oxidation number of 1, but when mixed with fewer electronegative elements, it becomes negative.
In most compounds, oxygen (O) has an oxidation number of 2, but peroxides have a -1.
A Group 1 element's oxidation number in a compound is one.
In a compound, a Group 2 element's oxidation number is +2.
A Group 17 element in a binary compound has an oxidation number of 1.
In a neutral molecule, all of the atoms' oxidation numbers add up to zero.
the total of a polyatomic particle's oxidation numbers
a) CuCO₃
Let Cu be in the oxidation state "x."
As, the oxidation number of carbon is (+4) and oxidation number of oxygen is (-2).
so CuCO₃=0
Cu+C+3O=0
x+ 4+3(-2) =0
x+(-2) =0
x =+2
Cu has an oxidation state of (+2)
b) CH₄
As, the oxidation number of hydrogen is (+1)
so, CH₄ =0
C+4H =0
C +4 = 0
C= -4
C is in the oxidation state (-4)
c) IF
I should be in the "x" oxidation state.
In a binary compound, a Group 17 element's oxidation number is -1. Iodine and fluorine both fall under the 17th category.
IF = 0
I+F+0
I+(-1) =0
I= +1
I is in the (+1) state of oxidation.
d) CH₂Cl₂
As, the hydrogen oxidation number and oxidation number of a Group 17 element (Cl) in a binary compound is -1.
CH₂Cl₂ =0
C+2H+2Cl =0
C +2+(-2) =0
C = 0
e) SO₂
As, the oxidation number of oxygen is (-2).
SO₂ =0
S+2O = 0
S +(-4) =0
S = +4
s is in the (+4) state of oxidation.
f). (NH₄)₂CrO₄
(NH₄)₂CrO₄ is from (NH₄)⁺ + CrO₄²⁻
so
NH₄ =+1, since hydrogen is +1
N+ 4H = +1
N +4 =+1
N = -3
and
CrO₄ = -2
Cr +4 O = +2, since O = -2
Cr +4 (-2) = -2
Cr+ (-8) = -2
Cr = +6
learn more about oxidation number at
brainly.com/question/15167411
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