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Which of the following statements about CH3OH and CH2O are true? The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces and dipole/dipole forces. Pure CH3OH will have a lower boiling point and a lower viscosity than pure CH2O. The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces only. Pure CH3OH will have a lower boiling point and a lower viscosity than pure CH2O. The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces, dipole/dipole forces, and hydrogen bonds. Pure CH3OH will have a lower boiling point and a lower viscosity than pure CH2O. The molecules of CH3OH can form London forces and dipole/dipole forces. The CH2O molecules can form London forces, dipole/dipole forces, and hydrogen bonds. Pure CH3OH will have a lower boiling point and a lower viscosity than pure CH2O. The molecules of CH3OH can form London forces only. The CH2O molecules can form London forces, dipole/dipole forces, and hydrogen bonds. Pure CH3OH will have a lower boiling point and a lower viscosity than pure CH2O. The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces and dipole/dipole forces. Pure CH3OH will have a higher boiling point and a lower viscosity than pure CH2O. The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces, dipole/dipole forces, and hydrogen bonds. Pure CH3OH will have a higher boiling point and a higher viscosity than pure CH2O. The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces and dipole/dipole forces. Pure CH3OH will have a higher boiling point and a higher viscosity than pure CH2O. The molecules of CH3OH can form London forces and dipole/dipole forces. The CH2O molecules can form London forces and dipole/dipole forces. Pure CH3OH will have a higher boiling point and a higher viscosity than pure CH2O. The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds. The CH2O molecules can form London forces and dipole/dipole forces. Pure CH3OH will have a lower boiling point and a higher viscosity than pure CH2O.

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The statements that are true are as follows:

The molecules of CH3OH can form London forces, dipole/dipole forces, and hydrogen bonds.

The CH2O molecules can form London forces and dipole/dipole forces

The molecules of CH3OH can shape London forces, dipole/dipole forces, and hydrogen bonds.(True) Methanol is a polar molecule (1.sixty nine D), and so it famous all 3 of the van der Waals forces,

1) London dispersion force (vulnerable), methanol is an natural compound with low polarity

2) dipole-dipole forces

3) hydrogen bond (strong),that is an severe kind of  dipole dipole interplay among partly nice hydrogen & partly negative oxygen withinside the methanol(CH3OH) molecule

The CH2O molecules can shape London forces and dipole/dipole forces.(True)

Formaldehyde(CH2O),like several atoms and molecules, may have very vulnerable London dispersion forces created as electrons shift withinside the electron cloud.as it possesses a everlasting dipole (primarily based totally at the polarized carbon-oxygen bond) formaldehyde additionally famous dipole-dipole interactions.

To learn more about dipole-dipole check the link below:

https://brainly.com/question/25902447

#SPJ4

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