Answered

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How do you evaluate [(1/(x)−(1/x^(2)+x))] as x approaches 0?

Sagot :

As x approaches 0, the denominator of the expression [(1/(x)−(1/x^(2)+x))] approaches infinity and the numerator approaches 0. Therefore, the expression approaches 0 as x approaches 0.

1. Evaluate the denominator of the expression [(1/(x)−(1/x^(2)+x))] as x approaches 0.

2. The denominator of the expression [(1/(x)−(1/x^(2)+x))] approaches infinity as x approaches 0.

3. Evaluate the numerator of the expression [(1/(x)−(1/x^(2)+x))] as x approaches 0.

4. The numerator of the expression [(1/(x)−(1/x^(2)+x))] approaches 0 as x approaches 0.

5. Therefore, the expression [(1/(x)−(1/x^(2)+x))] approaches 0 as x approaches 0.

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