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How do you evaluate ln(1/0.32)?

Sagot :

contexto1024

The value of natural logarithm, ln(1/0.32) where base "e" or e =2.7182 is 1.13943..

What is Logarithm function ?

Logarithm, an exponent or power that must be raised to obtain a particular number. Expressed mathematically, x is the logarithm of n in base a, where x = logₐ n.

  • Ln where bx = n is called the natural logarithm. Also called the base e logarithm. where e is an irrational number approximately equal to 2.718281828459... The natural logarithm (ln) is represented as ln(x).
  • Common Logarithms: Base 10

Basic Rules:

  • log(a) + log(b) = log(ab)
  • log(a) - log(b) = log(a/b)

Wehave given that,

ln(1/0.32) here , a = 1 , b = 0.32

using formula, ln(1/0.32) = ln(1) - ln(0.32)

Now, from logarithm table , log(1) = 0

log(0.32)= ln(0.32) = - 1.13943

ln(1/0.32) = ln(1) - ln(0.32) = 0-(- 1.13943)

=> ln(1/0.32) = 1.13943

Hence, the value of ln(1/0.32) is 1.13943.

To learn more about Logarithm function, refer:

https://brainly.com/question/19513407

#SPJ4

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