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Sagot :
The required straight equation will be y = -0.5x + 27.5 passes through the points (-5, 0) and (5, 2).
What are equations in a straight line?
A straight line's equation is given by y=mx+c, where c is the height at which the line intersects the y-axis (often referred to as the y-intercept) and m is the gradient.
According to the given graph,
We can see two points are (-5, 0) and (5, 2)
The linear equation will be: y - y₁ = (y₂ - y₁)/(x₂ -x₁ )[x -x₁]
Here
x₁ = -5, y₁ = 0
x₂ = 5, y₂ = 2
⇒ y - y₁ = (y₂ - y₁)/(x₂ -x₁ )[x -x₂]
Substitute values in the equation, we get
⇒ y - 0 = (2 - 0)/(8-4)(x-(-5))
⇒ y - 30 = (2)/(-4)(x + 5)
⇒ y - 30 = -1/2(x + 5)
⇒ y = (-1/2)x - 5/2 + 30
⇒ y = -0.5x + 27.5
Thus, the required equation will be y = -0.5x + 27.5 passes through the points (-5, 0) and (5, 2).
Learn more about straight line
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Write an equation for the graph shown in the form y=ax+b.
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