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Sagot :
The speed of a point on the rim is 2.44 m/s.
What is a quick answer for diameter?
The diameter is the distance along the circle's center that must travel in order to touch two points on its edge.
First convert diameter into radius
r = d/2 = 0.08/2 = 0.04 m
The moment of inertia of disc is given by
I = 0.5mr²
Where m is the mass and r is the radius of the disk
I = 0.5(0.1)(0.04)²
I = 0.00008 kg.m²
and since we are dealing with rotational motion then rotational kinetic energy is given by
E = 0.5 I ω²
we have to separate ω
ω² = E/0.5 I
ω = √E/0.5 I
ω = √0.15/0.5(0.00008)
ω = 61.23 rad/sec
Finally we know that speed is given as
v = ω r
v = 61.23 (0.04)
v = 2.44 m/s
Therefore, the speed of a point on the rim is 2.44 m/s.
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The complete question is -
A thin, 100 g disk with a diameter of 8.0 cm rotates about an axis through its center with 0.15 J of kinetic energy. What is the speed of a point on the rim
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