Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The force exerted per unit of area by a column of mercury is 1.01×10⁵ Pa and height of column that will exert same force is 10.3 m.
We will be using the formula mentioned below for both the calculations.
P = rho×g×h, where P is pressure, rho is density, g is acceleration due to gravity and h is height.
Firstly converting the units to m and kg.
Height = 76 cm
100 cm = 1 m
So, height = 0.76 m
Density = 13.59×(10²)³/10³
Density = 13590 kg/m³
Keep the value in formula for calculation pressure, which is force per unit area
Pressure = 13590×9.81×0.76
Performing multiplication
Pressure = 1.01×10⁵ Pa
Now finding height of column in case same force and liqui being water
Calculating density = 1×(10²)³/10³
Density = 1×10³ kg/m³
h = P/rho×g
h = 1.01×10⁵/(9.81×10³)
Performing division
height = 10.3 m
Hence, pressure is 1.01×10⁵ Pa and height is 10.3 m.
Learn more about gravitational force -
https://brainly.com/question/19050897
#SPJ4
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.