a) The correct option is A
The null hypothesis in the question states that the mean number of website searches does not differ between the day and evening advertisements and the alternative hypothesis states that the mean number of website searches differs between the day and evening advertisements. It can be written as:
[tex]H_{0} :[/tex] μ[tex]_{x}[/tex]-μ[tex]_{y}[/tex] = 0
[tex]H_{a} :[/tex] μ[tex]_{x}[/tex]-μ[tex]_{y}[/tex] ≠0
b-1) From the below excel output screenshot the t-test statistical value is I -0.3476.
b-2) From the below excel output the critical t value comes as 2.0017. So, the rejection region includes all the values greater than 2.0017 and less than -2.0017.
c) The calculated t-statistic value is not falling in the rejection region. So we do not reject the null hypothesis.
Do not reject [tex]H_{0}[/tex]. At the 5% significance level, we conclude the mean number of website searches not differ between the day and evening advertisements.
(The below excel screenshot shows the customized formula and the output which is required to find the values required to test the hypothesis.)
To learn more about the hypothesis visit:brainly.com/question/29519577
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