At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

the linear factors of the cubic are ✔ (x – 2)(x – 3)(x – 5) . to solve for the leading coefficient, use ✔ –5 = a(0 – 2)(0 – 3)(0 – 5) . a = ✔ 1/6 write the function: f(x) = x3 – x2 x –

Sagot :

For the linear factors of the cubic, which are (x - 2)(x - 3)(x – 5), the function will be f(x)=1/6x³–5/3x²+31/6x–5.

What is linear factors?

The first-degree equations that make up a polynomial's linear factors serve as the foundation for higher-order and more complicated polynomials. The formula for a linear factor is ax + b, and it cannot be factored further. A linear factor model establishes a linear equation-based relationship between the return on an asset (such as a stock, bond, mutual fund, or other type of investment) and the values of a small number of factors.

Here,

The linear factors of the cubic are  

=(x – 2)(x – 3)(x – 5)

To solve for the leading coefficient, use  

–5 = a(0 – 2)(0 – 3)(0 – 5)

a = 1/6

f(x)=1/6x³–5/3x²+31/6x–5

The function will be f(x)=1/6x³–5/3x²+31/6x–5 for the the linear factors of the cubic that is (x – 2)(x – 3)(x – 5).

To know more about linear factors,

https://brainly.com/question/2510777

#SPJ4