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Sagot :
The sum of the infinite geometric series 16 + 12 + 9 + ... is 64.
To find the sum of an infinite geometric series, you can use the formula:
sum =[tex]\frac a{(1 - r)}[/tex]
where "a" is the first term in the series and "r" is the common ratio between terms.
In this case, the first term is 16 and the common ratio is 3/4, so the sum is:
sum [tex]= \frac{16}{(1 - \frac{3}4)} =\frac{16}{(\frac{1}4)} = 64[/tex]
Therefore, the sum of the infinite geometric series 16 + 12 + 9 + ... is 64.
Note that this formula is only valid if the absolute value of the common ratio is less than 1. If the absolute value of the common ratio is 1 or greater, the series will either converge to a finite value or diverge to infinity, and the sum cannot be calculated using this formula.
To learn more about geometric series, visit:
brainly.com/question/4617980
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