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Sagot :
The linear equation that passes through the points (0,-8) and (5,-5) is:
y = (3/5)*x - 8
How to find the equation of the line?
A general linear equation is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
If the line passes through two points (x1, y1) and (x2, y2), then the slope is:
a = (y2 - y1)/(x2 - x1)
Here we have the two points: (0,-8) and (5,-5)
Then the slope is:
a = (-5 + 8)/(5 - 0) = 3/5
And because of the point (0, -8) we know that the y-intercept is -8, then the linear equation is:
y = (3/5)*x - 8
Learn more about linear equations:
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