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Sagot :
If the freezer operates for 6 hours each day then the power it requires for operating is (p) = 401.82W
If the freezer keeps its interior at a temperature of -6.0C in a 20.0C room, the theoretical maximum performance coefficient is (k) = 7.1
the theoretical maximum amount of ice this freezer could make in an hour, starting with water at 20.0C(m) = 24.58Kg
(a) Given energy of freezer (E) per year= 880 kW*h = 880x10^3 w*h
Time to operate = 6hrs per day
Power (P) = 880x10^3/(365x6) = 880x10^3/2190 = 401.82W
(b) Given T = -6+273 = 257K and T' = 20+273 = 293K
Coefficient(k) = T/T'-T = 257/293-257 = 7.1
(c) Q = mCwdT+mL
Q = 1kg(4190)(293-273)+1kg(3.34x10^3) = 417800J
heat removal(Qrem) = powerxk
Qrem = 401.82x7.1 =2852.922J
Mass of ice = Qrem/Q = 2852.922x3600/417800 = 24.58kg
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