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Sagot :
The variance of a sample is 4,096. And for interquartile, the difference between the largest and smallest values. The correct answer is option D
To calculate the variance we have a small formula:
v=s^2-----(1)
v=variance
s=Standard deviation
so, given that s=64
substitute in equation(1)
v=64*64
v=4096.
variance: The variance is a measure of variability. It is calculated by taking the average of squared deviations from the mean.
Variance is denoted by a symbol: σ2.
Interquartile range (IQR) is a measure of statistical dispersion, which is used to spread the data. The IQR is also called midspread.
To calculate the IQR, the data set is divided into quartiles. These quartiles are denoted by Q1 (another name is the lower quartile), Q2 (the median), and Q3 (also called the upper quartile). The lower quartile corresponds with the 25th percentile and the upper quartile corresponds with the 75th percentile, so IQR = Q3 − Q1
To know more about Variance:
https://brainly.com/question/16162584
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