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Find each of these values. a) (19² mod 41) mod 9 b) (32³ mod 13)² mod 11 c) (7³ mod 23)² mod 31 d) (21² mod 15)³ mod 22

Sagot :

The remainder will be 33, 9, 7, and 14 for options a, b, c, and d respectively.

The Remainder is the extra part of a number that restricts the number to be divided completely.

a)

(19² mod 41) mod 9

Let us determine 361 mod 41

a=361 = 328+33= 8*41+33 =8d+33

The remainder is the constant in the final expression: 361 mod 41=33

33 mod 9 = 6 (since a=33= 27+6=3*9+6=3d+6)

b)

(32³ mod 13)² mod 11

Let us determine 32 mod 13

a=32=26+6=2*13+6+2d+6

The remainder is the constant in the final expression: 32 mod 13=6

[tex](6^{3} mod13)^{2} mod 11\\(216mod13)^{2} mod 11[/tex]

Let us determine 216 mod 13

a= 216= 208+8=16*13+8 = 16d+8

The remainder is the constant in the final expression: 216 mod 13=8

[tex]8^{2} mod 11\\64 mod 11[/tex] = 9 (since, 64= 55+9= 11*5+6= 11d+6)

c)

(7³ mod 23)² mod 31

[tex](343mod23)^{2} mod 31\\[/tex]

Let us determine 343 mod 23

a=343=322+21=14*23+21=14d+21

The remainder is the constant in the final expression: 343 mod 23= 21

[tex]21^{2} mod 31 = 441 mod 31=7[/tex] (since a = 441=434+7=14*31+7=14d+7)

d)

(21² mod 15)³ mod 22

[tex](441mod15)^{3} mod 22[/tex]

Let us determine 441 mod 15

a=441 = 435+6= 29*15+6= 29d+6

The remainder is the constant in the final expression: 441 mod 15= 6

[tex]6^{2} mod 22=36mod22= 14[/tex] (since a = 36= 22+14= 1*22+14= d+14)

To know more about remainders visit: brainly.com/question/17162878

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