Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
The capacitance if an insulator with dielectric constant κ and thickness d/2 is slipped between the electrodes C = 2K∉A/d
Let A represent the cross-sectional area of the electrodes.
Let C stand for capacitance.
The electric field between the electrodes is denoted by E.
Be the charge per unit area, sigma.
be the permittivity of empty space, and K is assumed to be an insulator's dielectric constant in the question.
It is inserted between the electrodes as d/2.
the current electric field between electrodes.
E equals sigma /2 plus sigma /2.
E = sigma/ ——— As we are aware, E = V /(d/2)
V=E d/2 V=sigma /*d/2
V = dsigma/2 ——— Once more, we are aware of 2.
C = Q/V
C is equal to sigma A/(sigma d/2) Q = sigma A (from equation 2
For an insulator with a dielectric constant of K, C = 2A/d.
C = 2K∉A/d
Learn more about capacitance here:
https://brainly.com/question/12644355
#SPJ4
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
