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Sagot :
The capacitance if an insulator with dielectric constant κ and thickness d/2 is slipped between the electrodes C = 2K∉A/d
Let A represent the cross-sectional area of the electrodes.
Let C stand for capacitance.
The electric field between the electrodes is denoted by E.
Be the charge per unit area, sigma.
be the permittivity of empty space, and K is assumed to be an insulator's dielectric constant in the question.
It is inserted between the electrodes as d/2.
the current electric field between electrodes.
E equals sigma /2 plus sigma /2.
E = sigma/ ——— As we are aware, E = V /(d/2)
V=E d/2 V=sigma /*d/2
V = dsigma/2 ——— Once more, we are aware of 2.
C = Q/V
C is equal to sigma A/(sigma d/2) Q = sigma A (from equation 2
For an insulator with a dielectric constant of K, C = 2A/d.
C = 2K∉A/d
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