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ABCD is a rhombus. M is the point on [AD] such that [CM] bisects angle ACD. Show that angle DMC is 3 time larger than angle ACM

Sagot :

gouthami123

In a rhombus, all sides are the same length, and the opposite angles are equal. The diagonals also bisect each other at 90 degrees.

What is the specialty of angle in a rhombus?

We know that,

A rhombus has two congruent acute and two congruent obtuse angles.

Here we use the terms  x and y to represent the angles.

where x is the acute angle

The angles total 360 degrees.

So far, we have:

2(x+y) = 360

By dividing both sides by 2 , we get,

x + y = 180

We can assume y is 3 times larger than x,

That is y = 3x

As a result, the equation becomes,

x + 3y = 180

Calculate the total

4x = 180

As a result, the acute angle is 45 degrees.

Hence we proved that y is 3 times larger than x.

To learn more about rhombus refer to :

https://brainly.com/question/12189679

#SPJ1

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