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what is the REDUCED mass of H2 and N2 using Ma*Mb/Ma+Mb

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The reduced mass of H2 and N2 is 1.86g.

What is reduced mass?

In Newtonian mechanics' two-body problem, the reduced mass is the "effective" inertial mass. It is a quantity that makes it possible to solve the two-body problem as if it were a one-body problem. However, the mass that determines gravitational pull is not lowered. It is denoted by μ.

It is given by equation:

1 / μ = 1 / m1 + 1 / m2

μ = [tex]\frac{m1 * m2}{m1 + m2}[/tex]

According to the question,

Molar mass of H2 = 2

Molar mass of N2 = 28

Substituting the values in equation:

μ = [tex]\frac{2 * 28}{2 + 28}[/tex]

μ = [tex]1.86 g[/tex]

The reduced mass of H2 and N2 is 1.86g.

To know more about reduced mass, check out:

https://brainly.com/question/14773251

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