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Sagot :
The Coefficient of friction u = 0.078
Calculate the following?
Radius of curvature r = 200 m
First we need banking angle at v = 60 Km/h = 60(1000 m/3600 s) = 16.66 m/s
At this speed (for which the road is designed)
Coefficient of friction v^2/rg = sin A
sin A = (16.66)^2/(200*9.8)
sin A = 0.1416
A = 8.141 degrees
For no slipping at the banking angle at the lower Speed v = 40 Km/h = 40 (1000 m/3600 s) =11.11 m/s ,
mv^2/r = mg sin A - u mg cos A
0.617 = (9.8*0.1416) - u (0.9899*9.8)
0.617 = 1.387 - u (9.7)
9.78 u = 0.77
∴ Coefficient of friction u = 0.078
To know more about friction, visit:
https://brainly.com/question/24338873
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