Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
(a) ball velocity = - 2.47 m/s
(b) block velocity = 1.236 m/s
What is collision?
Two items collide when they briefly come into touch with one another. To put it another way, a collision is a brief reciprocal encounter between two masses in which the momentum and energy of the masses change.
For ball as it is at initially at height of 70.0 cm = 0.7 m
so by energy conservation,
K.E.(i) P.E.(i) + K.E.(f)+P.E.(f)
0 + mg×(0.7) = 1/2 mv² + 0
v = 3.71 m/s
now, collision b/w ball and block
as the block is in rest initially and there is no external force b/w them
so by momentum conservation,
m₁u₁+ m₂u₂ = m₁v₁+ m₂v₂
or, (0.5 x 3.71) + 0 = (0.5x v₁) + (2.5 x v₂)
3.71 = v₁ + 5v₂ .........(1)
as elastic collision so energy conservation
or, 1/2 m₁ u₁² + 1/2 m₂ u₂² = 1/2 m₁ v₁² + 1/2 m₂ v₂²
or, (1/2 x 0.5 x 3.712) + 0 = (1/2 x 0.5 x v₁²) + (1/2 x 2.5 x v₂²)
or, 3.433 = 0.25xv₁² + 1.25 v₂² ...............(2)
from eq. 1 and eq. 2
or, 3.433 = 0.25 x (3.71 - 5 v₂)² + 1.25v₂²
or, v² = 1.236 m/s
and v₁ = 3.71 - 5v₂
or, v₁ = - 2.47 m/s
so after collision
ball velocity = - 2.47 m/s [(-)ve x direction]
block velocity = 1.236 m/s [(+)ve x direction]
To know more about velocity refer to:
https://brainly.com/question/24445340
#SPJ1
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
