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Sagot :
The downward force of magnitude must be applied to the small piston for the lift to raise a load whose weight is Fg = 15.0 kN is 225N.
Given that,
The small piston of a hydraulic lift has a cross-sectional of 3.00 cm^2.
And its large piston has a cross-sectional area of 200 cm^2.
Based on the above information, the calculation is as follows:
Here we use the Pascal's principle,
........... (1)
Here
F denoted Force exerted on the larger piston,
f denoted force that applied to the smaller piston,
A denoted cross-sectional area of the larger piston,
And, a denoted cross-sectional area of the smaller piston.
Now
= 225 N
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