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Sagot :
The radius of the circle when stringe break is 6.93×10^-2.
What is radius?
The radius is the distance from the centre of a circle.
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is 6.9.3×10^-3m
Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
centripetal force =m.v^2/r
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
r=m.v^2/centrigual force =6.93×10^-2
The radius of the circle when, the string breaks r = =6.93×10^-2.
To know more about radius click-
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