Answered

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a bullet is shot into a large lead block and comes to rest (the block remains at rest as the bullet embeds in it). temperature measurement of the block shows that the bullet lost 1,729 j of kinetic energy and motion sensors show that it was moving at 597 m/s just as it hit the block. what is the mass of the bullet in grams?

Sagot :

The mass of the bullet is 9.7 grams.

As total mechanical energy is the sum of all the kinetic as well as potential energy stored in the system.

                                             i.e.ME = KE + PE

As given in the problem bullet is fired into a large stationary absorber and comes to rest. So PE = 0.

Temperature measurements of the absorber show that the bullet lost 1729 J of kinetic energy and high-speed photos of the bullet show that it was moving at 597 m/s just as it struck the absorber.

We know that KE = [tex]\frac{1}{2} mv^{2}[/tex], where

KE = kinetic energy = 1729J

m = mass

v = velocity = 597 m/s

Putting these values in above equation we get, m = 9.7 grams

So, the mass of the bullet is 9.7 grams.

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