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What is the magnitude B of the magnetic field at the location of the charge due to the current-carrying wire? Express your answer in teslas. View Available Hint(s) V AED + ? BB = V\rm{T}) Learning Goal:
To practice Problem-Solving Strategy 24.2 Magnetic force problems A long straight horizontal wire carries a current I = 1.20 A to the left. A positive 1.00 C charge moves to the right at a distance 5.00 m above the wire at constant speed v = 5000 m/s. (Figure 1) What are the magnitude and the direction of the magnetic force on the charge?

Sagot :

The magnitude of the magnetic field on the charge: 4.8 × 10⁻⁸ T

What is magnetic field?

The magnetic field is a zone surrounding a magnetic substance or a moving electric charge where magnetism acts. Moving electric charges and magnetic dipoles combine to form a magnetic field, which acts as a force field on other adjacent moving charges and magnetic dipoles.

B and H are used to denote the magnetic field. The SI units for B and H are Newtons per meter per ampere or Teslas, respectively.

Here, by right hand rule, the magnetic field around the wire which will be into the location.

Thus, the magnitude of the magnetic field,

B = μ(0)I/2πr

or, B = [(4π × 10 ⁻⁷) × (1.20)] ÷ [2π(5.00)]

or, B = 4.8 × 10⁻⁸ T

To know more about magnetic field refer to:

https://brainly.com/question/7802337

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