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A desktop computer is to be cooled by a fan whose flow rate is 0.34 m^3/min. Determine the mass glow rate of air through the fan at an elevation of 3400 m where the air density is 0.7 kg/m^3. Also, if the average velocity of air is not to exceed 110 m/min, determine the diameter of the casing of the fan. Answers: 0.238 kg/min, 6.3 cm

Sagot :

The mass flow rate to cool the desktop computer s 0.238kg/min and if the average velocity does not exceed 110m/min the diameter of fan casing is 6.3 cm.

What is mass flow rate?

The mass of a substance that moves per unit of time is known as the mass flow rate in physics and engineering. In SI units, it is measured in kilograms per second; in US customary measures, it is measured in slugs or pounds per second. The standard symbol is m (pronounced "m-dot"), though (Greek lowercase mu) is also occasionally used. See, for instance, Schaum's Outline of Fluid Mechanics, where mass flow rate is sometimes referred to as mass flux or mass current.

Since its known to us that;

Flow rate V = 0.34 [tex]m^{3}/min[/tex]

density of air ρ = 0.7 [tex]kg/m^{3}[/tex]

average velocity of air  [tex]v_{avg}[/tex]= 110 m/min

Mass flow rate is given by

m =  ρ x V

m = 0.7 x 0.34

m = 0.238 kg/min

Since Flow rate can be written as

V = A.[tex]v_{avg}[/tex]

Where A denotes Area of cross-section

0.34 = [tex]\frac{\pi d^{2}}{4}[/tex][tex]v_{avg}[/tex]

0.34 =[tex]\frac{\pi }{4} (d^{2})[/tex] x 110

d = 0.0626 m

d= 62.6 = 63 mm

Thus, we conclude that mass flow rate to cool the desktop computer s 0.238kg/min and if the average velocity does not exceed 110m/min the diameter of fan casing is 6.3 cm.

To know more about flow rate refer.

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