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A monochromatic light source with a power output of 59.0W radiates light of wavelength 600nm uniformly in all directions.
A. Calculate Bmax for the light at a distance of 5.10m from the source.
B. Calculate Emax for the light at a distance of 5.10m from the source.

Sagot :

A monochromatic light source with a power output of 59.0W radiates light of wavelength 600nm uniformly in all directions.

A. B(max) = 3.89 × 10⁻⁸ T

B. E(max) = 11.67 N/C

What is monochromatic light source?

Single-wavelength light sources are known as monochromatic lights, where mono stands for only one and chroma for color. Monochromatic lights are defined as visible light that falls within a certain range of wavelengths. It has a wavelength that falls within a constrained wavelength range.

The whole spectrum is theoretically included in each higher-order maximum, but because of potential partial overlap with the next-order maximum, it can be challenging to identify the pattern for a given color. Monochromatic lighting solves this issue.

The intensity of the wave is calculated as:

I = P/A

or, I = P/4πR²

or, I = 59.0 W/ 4π(5.10m)²

or, I = 0.1805 W/m²

A. Emax for the light at a distance of 5.10m from the source.

E(max) = [tex]\sqrt{2u_0cI}[/tex]

or, E(max) = 11.67 N/C

Where, [tex]u_0[/tex] = 4π × 10⁻⁷ T.m/A

c = 3 × 10⁸ m/sec

I = 0.1805 W/m²

B. The amplitude of the magnetic field is calculated as follows:

B(max) = E(max)/c

or, B(max) =  (11.67 N/C) / (3 × 10⁸ m/sec)

or, B(max) = 3.89 × 10⁻⁸ T

To know more about monochromatic light source refer to:

https://brainly.com/question/13156018

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