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The freezing point of benzene is 278.7 K. At 260 K, an equimolar mixture of m-hexane and carbon tetrachloride contains 10 mol % benzene. Calculate the partial pressure of benzene in equilibrium with this mixture. For benzene: Apush = 30.45 cal gº: Pola ( 260 K) -0.0125 bar. At 25°C:

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The partial pressure of benzene in equilibrium with this mixture is 0.0107 bar

Calculate the molar fraction of benzene in the equimolar mixture.

At 260 K, the equimolar mixture contains 10 mol % benzene, which is equal to 0.1 moles of benzene in a total of 1 mole of the mixture.

Calculate the vapor pressure of the mixture.

At 260 K, the vapor pressure of the mixture can be determined using the Clausius-Clapeyron equation:

Pmix = (30.45 cal g°·K·mol-1)·(0.0125 bar)·exp(-(278.7 K - 260 K)/(260 K))

Pmix = 0.1068 bar

Calculate the partial pressure of benzene in the mixture.

The partial pressure of benzene in the mixture can be calculated by multiplying the vapor pressure of the mixture by the molar fraction of benzene in the mixture:

Pbenzene = Pmix·xbenzene

Pbenzene = 0.1068 bar·(0.1 moles of benzene / 1 mole of mixture)

The partial pressure of benzene = 0.0107 bar

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