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given the system of inequalities below, determine the shape of the feasible region and find the vertices of the feasible region. report your vertices starting with the one which has the smallest x-value. if more than one vertex has the same, smallest x-value, start with the one that has the smallest y-value. proceed clockwise from the first vertex. leave any unnecessary answer spaces blank. x+y<5 8x + y >7 x >0 y>0 The feasible region is Unbounded The first vertex is The second vertex is The third vertex is The fourth vertex is

Sagot :

varshamittal029

The area on the graph that is not shaded is the region of feasibility. The shape is a triangle and the vertices of the feasible region are: (5,1.5), (.75,.75), (1.5,.5)

The system of inequalities below, We need to determine the shape of the feasible region and find the vertices of the feasible region

x+y<=2

3x+y>=3

x+3y>=3

x>=0

y>=0

Now, we would graph with the following inequalities

x+y>=2

3x+y<=3

x+3y<=3

x<=0

y<=0

Therefore, the area on the graph that is not shaded is the region of feasibility and the shape is a triangle, the vertices of the feasible region are: (5,1.5) (0.75, 0.75), (1.5,.5).

To learn more about linear equation refer here

https://brainly.com/question/14323743

#SPJ4

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