Each metal is illuminated with 400 nm (3.10 eV) light. Rank the metals on the basis of the maximum kinetic energy of the emitted electrons. (If no electrons are emitted from a metal, the maximum kinetic energy is zero, so rank that metal as smallest.) Rank from largest to smallest. To rank items as equivalent, overlap them. The correct ranking cannot be determined.

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06-12-2022
Physics

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Each metal is illuminated with 400 nm (3.10 eV) light. Rank the metals on the basis of the maximum kinetic energy of the emitted electrons. (If no electrons are emitted from a metal, the maximum kinetic energy is zero, so rank that metal as smallest.) Rank from largest to smallest. To rank items as equivalent, overlap them. The correct ranking cannot be determined.

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kjuli1766 kjuli1766 · Answer 1 · 2022-12-14T02:12:39-05:00

The metals on the basis of the maximum kinetic energy of the emitted electrons is Cesium > potasium > Beryllium = aluminum = Megnesium = Platinum.

From Einstein photo electic effect equation

E = 3.1 eV

E = Wo+ Kmax

Kmax = E - Wo

For Be: E< Wo, Kmax = 0

There is no emission of photo electron

For K : Kmax = 3.1 -2.3 = 0.8 eV

For Al : E< Wo, Kmax = 0

There is no emission of photo electron

For Mg: E< Wo, Kmax = 0

There is no emission of photo electron

For Cs: Kmax = 3.1 -2.1 = 1.0 eV

For Pt : E< Wo, Kmax = 0

There is no emission of photo electron

Cesium > potasium > Beryllium = aluminum = Megnesium = Platinum

Einstein photo electic effect:

Einstein said that energy is a beam of particles related to frequency according to Planck's formula. When this beam is directed at a metal, photons collide with atoms. If the photon frequency is high enough to knock off an electron, the collision will produce the photoelectric effect.

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