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a manufacturer of transistors claims that its transistors will last an average of 1000 hours. to maintain this average, 25 resistors are tested each month. you may assume that the distribution of the lifetime of a transistor is normal. what conclusions can you draw from a sample that has a mean of 1010 and a standard deviation of 60?

Sagot :

Do not reject H(0). There is not sufficient evidence to a manufacturer of transistors claims that its transistors will last an average of different than 1000 hours. at 0.01 significance level.

In the given question, a manufacturer of transistors claims that its transistors will last an average of 1000 hours.

To maintain this average, 25 resistors are tested each month.

We may assume that the distribution of the lifetime of a transistor is normal.

We have to calculate a sample that has a mean of 1010 and a standard deviation of 60.

So let us consider

X : Life time of a transistor

So we have

N=25

x=1010

s=60

Since sample size n(25≤30) is small and population standard is unknown so we use t statistic for hypothesis testing.

Now our null and alternate hypotheses are given as:

H(0): μ=1000

H(1): μ≠1000 (two tailed test)

Under Null hypothesis our test statistic is;

t=(x-μ)/(s/√n)

t=(1010-1000)/(60/√25)

t=0.83

Critical Value:

t(α,(n-1))=t(0.01, 24)

t(α,(n-1))=2.80

We have given level of significance α=0.01 and also we find the t-score 0.83 and degree of freedom=24

p value

The Excel formula is used to calculate the p value is:

P value =2×(1- (t(24) > 0.83))

P value =2×(1-0.7926)

P value =2×0.2074

P value =0.4147

Since p value=0.42 greater than α=0.01 means that deviation from the null hypothesis is not statistically significant, and the null hypothesis is not rejected and we claims that its transistors will last an average of 1000 hours.

To learn more about null hypothesis link is here

brainly.com/question/29657446

#SPJ4

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