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Three long wires (wire 1 wire 2 and wire 3 ) hang vertically. The distance between wire 1 and wire 2 is 23.0 cm On the left, wire 1 carries an upward current of 1.50 A. To the right, wire 2 carries a downward current of 3.60 A. Wire 3 is to be located such that when it carries a certain current, each wire experiences no net force. (a) Is this situation possible? Is it possible in more than one way? Describe (b) the position of wire 3 and the magnitude and direction of the current in wire 3.

Sagot :

Based on the combination technique,

1. The position of wire 3

2. The magnitude and direction of current in wire 3

Combination method:

In statistics, the mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter is know a combination method.

Given,

Here we have the three long wires hang vertically. The distance between wire 1 and wire 2 is 23.0 cm On the left, wire 1 carries an upward current of 1.50 A. To the right, wire 2 carries a downward current of 3.60 A. Wire 3 is to be located such that when it carries a certain current, each wire experiences no net force.

And now we need to find the position of wire 3 and the magnitude and direction of the current in wire 3.

As per the given question, we know that the

=> Current in wire 1, i1 =1.2A upward

=> Current in wire 2, i2=5A downward

And the distance between wire 1 and 2 is calculated is

=> 20cm = 0.2m

Here the current is calculated as

=> F/l = μo•i1•i3/2πx

So,

=> F/l=6×10⁻⁶N/m

=> 6×10⁻⁶ = μo•i1•i3/2πx

=> 6×10⁻⁶ =4π×10⁻⁷×1.2×i3/(2π×0.0632)

When we do Cross multiply,

=> 6×10⁻⁶×2π0.0632=4π×10⁻⁷×1.2×i3

=> 2.383×10⁻⁶=4π×10⁻⁷×1.2×i3

=> i3= (2.383×10⁻⁶)/(4π×10⁻⁷×1.2)

Therefore, i3= 1.58A and it's direction is downward.

To know more Combination method here.

https://brainly.com/question/28998705

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