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Which of the following complex numbers is equal to (5 + 12i) − (9i^2 − 6i), for i √ -1 ?

Which Of The Following Complex Numbers Is Equal To 5 12i 9i2 6i For I 1 class=

Sagot :

Complex number equal to (5 + 12i) − (9i^2 − 6i), for i = √ -1 is 14 + 18i.

Complex numbers are the numbers that are expressed in the form of a+ib where, a,b are real numbers and  ‘i’ is an imaginary number called “iota”. The value of i = (√-1)

Given number is (5 + 12i) − (9i^2 − 6i).

We know that i^2 = -1.

Using this we get number = 5+12i+9+6i

                                           = 14+18i

So the required number is 14 + 18i.

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