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You have been given the task of organizing a poll regarding an upcoming election. The object is to estimate the proportion of the country that will vote to keep the current government in power. You have been told to collect a sample and find a 95% confidence interval for the proportion. This interval is allowed to have a margin of error of 3%. A preliminary investigation suggests that the proportion of people that will vote to keep the current government is 0.74. a) Calculate the minimum sample size that is required in this survey. Give your answer as a whole number. Someone working on your team reports that the information suggesting that the proportion of people that will vote to keep the current government is equal to 0.74 is out of date. In fact, some recent events in politics mean that there is no safe guess at what the proportion might be. b) Based on this new information, calculate the minimum sample size that is required in this survey. Give your answer as a whole number.

Sagot :

varshamittal029

The confidence interval for the task of organizing the poll for the upcoming elections be,

(222.117 , 257.883)

Given, You have been given the task of organizing a poll regarding an upcoming election.

The object is to estimate the proportion of the country that will vote to keep the current government in power.

You have been told to collect a sample and find a 95% confidence interval for the proportion.

This interval is allowed to have a margin of error of 3%. A preliminary investigation suggests that the proportion of people that will vote to keep the current government is 0.74.

We have to find the confidence interval,

Subtract 1 from your sample size. 10 – 1 = 9.

Subtract the confidence level from 1, then divide by two.

(1 – .95) / 2 = .025

For 9 degrees of freedom df and α = 0.025, margin of error is 2.262.

Divide your sample standard deviation by the square root of your sample size.

25 / √(10) = 7.90569415

Now, Multiply 2.262 × 7.90569415 = 17.8826802

For the lower end of the range

240 – 17.8826802 = 222.117

For the upper end of the range

240 + 17.8826802 = 257.883

Hence, the confidence interval be (222.117 , 257.883)

Learn more about Confidence Interval here https://brainly.com/question/26658887

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