Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

An inventive child named Nick wants to reach an apple in a tree without climbing the tree. Sitting in a chair connected to a rope that passes over a frictionless pulley (see figure below), Nick pulls on the loose end of the rope with such a force that the spring scale reads 310 N. Nick's true weight is 290 N, and the chair weighs 160 N. Nick's feet are not touching the ground.
(b) Show that the acceleration of the system is upward. (Do this on paper. Your instructor may ask you to turn in this work.)
Find its magnitude.
m/s2
(c) Find the force Nick exerts on the chair.
N


Sagot :

b) The magnitude of the acceleration of system is [tex]3.7m/s^2[/tex].

c)The force exerted by nick on the chair is 89.483 N.

Given,

weight of nick = 290 N

Weight of chair = 160 N

Spring scale force ,T = 310 N

then,

Total weight = 290+160= 450 N

b)

then the total mass be

Mass ,[tex]m = \frac{weight}{force}= \frac{450}{9.8} = 45.918 Kg[/tex]

By adding the forces of both ropes, the upward force can be calculated.

Net upward force = 310 + 310 = 620 N

The downward force can be calculated by adding the forces generated by Nick and its chair.

Net downward force = 290 + 160 = 450 N

Then, the resultant force be,

F = Net upward force - Net downward force = 620 - 450 = 170 N                    

To determine acceleration use formula,

[tex]F=ma\\\\45.918*a = 170\\\\a = \frac{170}{45.918} = 3.7 m/s^2[/tex]

Because net upward force exceeds net downward force, the resultant force is directed upwards thus the acceleration is  also upward.

c)

The force exerted by nick on the chair can be calculated by

F = n + T - 290\\\\

ma=n+T-290

Here, consider only nick's weight then mass will be

[tex]m=\frac{290}{9.8}=59.591 kg[/tex]

[tex]59.591*3.7=n+310-290\\\n=89.483 N[/tex]

Thus, the force exerted by nick on the chair is 89.483 N

To learn more about acceleration refer here

https://brainly.com/question/13994157

#SPJ4

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.