Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
b) The magnitude of the acceleration of system is [tex]3.7m/s^2[/tex].
c)The force exerted by nick on the chair is 89.483 N.
Given,
weight of nick = 290 N
Weight of chair = 160 N
Spring scale force ,T = 310 N
then,
Total weight = 290+160= 450 N
b)
then the total mass be
Mass ,[tex]m = \frac{weight}{force}= \frac{450}{9.8} = 45.918 Kg[/tex]
By adding the forces of both ropes, the upward force can be calculated.
Net upward force = 310 + 310 = 620 N
The downward force can be calculated by adding the forces generated by Nick and its chair.
Net downward force = 290 + 160 = 450 N
Then, the resultant force be,
F = Net upward force - Net downward force = 620 - 450 = 170 N
To determine acceleration use formula,
[tex]F=ma\\\\45.918*a = 170\\\\a = \frac{170}{45.918} = 3.7 m/s^2[/tex]
Because net upward force exceeds net downward force, the resultant force is directed upwards thus the acceleration is also upward.
c)
The force exerted by nick on the chair can be calculated by
F = n + T - 290\\\\
ma=n+T-290
Here, consider only nick's weight then mass will be
[tex]m=\frac{290}{9.8}=59.591 kg[/tex]
[tex]59.591*3.7=n+310-290\\\n=89.483 N[/tex]
Thus, the force exerted by nick on the chair is 89.483 N
To learn more about acceleration refer here
https://brainly.com/question/13994157
#SPJ4
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.