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Assuming bicycle tires are perfectly flexible and support the weight of bicycle and rider by pressure alone, calculate the total area of the tires in contact with the ground. The bicycle plus rider has a mass of 62.0 kg, and the gauge pressure in the tires is 3.50×105 Pa.

Sagot :

The total area of tires in contact with the ground is [tex]17.36 cm^2[/tex] when mass of bicycle rider is 62 kg and pressure of tires is [tex]3.5*10^5 pascal[/tex]

Pressure is the amount of force exerted on surface per unit area. It can also be defined as the force-to-area ratio (over which the force is acting).

Given,

Mass of the bicycle rider = 62.0 kg

pressure in tires = [tex]3.50*10^5\ N/m^2[/tex] (1 pascal = 1 [tex]N/m^2[/tex])

From definition of pressure,

[tex]P=\frac{F}{A}.....i[/tex]

Where, p=pressure ,F= force applied and A= area perpendicular to force

Force can be determined by formula,

[tex]F=mg....ii[/tex]

Where, m= mass and g= gravitational acceleration=9.8m/s^2

substituting eq.ii in eq.i,

[tex]P=\frac{mg}{A}\\\\A=\frac{mg}{P}\\\\A=\frac{62*9.8}{3.5*10^5}\\\\A=\frac{607.6}{3.5*10^5}\\\\A=0.001736m^2=17.36cm^2[/tex]

Thus, the area of tires in contact with the ground is [tex]17.36 cm^2[/tex]

To learn more about pressure refer here

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