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White light (400-700 nm) incident on a 600 line/mm diffraction grating produces rainbows of diffracted light.
What is the width of the first-order rainbow on a screen 2.0 m behind the grating?


Sagot :

the width of the first-order rainbow on a screen 2.0 m behind the grating is Δy=0.431m

Briefly:-

Finding the angle from a diffraction grating with split space d is necessary to get the fringe location ym.

dSinα=mλ

Slit spacing for a grating with N slits or lines per mm is

d=1/N

d=(1/600mm)

d=1.67×10⁻³mm

At a wavelength of 400 nm:

α=Sin⁻¹(mλ/d)

α=13.9°

The first order lowest wavelength fringe is located in the following location on the screen:

y1= Ltanα

y1=.49445m

For 700nm wavelength:

α=Sin⁻¹(mλ/d)

α=24.8°

The first order highest wavelength fringe is located in the following location on the screen:

y2= Ltanα

y2= .99255m

The first order lowest and highest wavelength fringe's difference is

Δy=(0.925595 - 0.49445)m

Δy=0.431m

To know more  about diffraction  visit:-

https://brainly.com/question/12290582

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