Answered

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there are 6 students in the class. one of them is to be selected as the best student and another student is to be selected as a runner-up. how many different ways can this be done?

Sagot :

If there are 6 students and one is selected for best student and another is selected for runner up, then 15 different ways that we can arrange the students

Total number of students in the class = 6 students

Number of students for best student = 1 student

Number of students for runner up = 1 students

Total number of students needed = 2

Here we have to use the combination

6[tex]C_2[/tex] = 6! / 2!(6 - 2)!

= 6! / 2! × 4!

Split the terms and cancel it

= 6 × 5 / 2 × 1

Multiply the terms

= 30 / 2

Divide the numbers

= 15 combinations

Therefore, there are 15 combinations

Learn more about combination here

brainly.com/question/28720645

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