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Sagot :
The town of Natrium, West Virginia, derives its name from the sodium produced in the electrolysis of molten sodium chloride(NaCl) mined from ancient salt deposits. The number of kilowatt-hours of electricity required to produce 5.50kg of metallic sodium from the electrolysis of molten NaCl(s) is 4.58 kWh when the applied emf is 5.00V
The reaction equation is given as:
Na⁺ +e⁻ ⇒ Na
So moles of Na equals moles of electrons used
So the number of moles of sodium can be calculated as:
number of moles = mass ÷ molar mass
Moles = 5500 g ÷ 23 g/mol (1 kg = 1000 g)
Number of moles = 239.13 moles
Q = n × F; where F represents the Faraday constant
Q = 239.13 moles × 96500 C
Q = 23,976,045 mol C
The relationship between electrical energy and Q is
E = Q x V
Now we can substitute the given value into the above formula and calculate the current value as follows:
E = 23,976,045 × 5 .50
E = 126,918,248 J
As 1 J = 2.77 × 10⁻⁷ kWh
For this reason;
126,918,248 J ÷ 2.77 × 10⁻⁷ kWh =4.58 kWh
From this we can conclude that 4.58 kWh of power is required to produce 5.50 kg of metallic sodium from the electrolysis of molten NaCl(s).
Learn more about electrolysis. click here:
Brainly.com/question/12629784
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