Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The probability of getting exactly 4 heads is 0.26
A loaded coin has 0.48 probability of coming up heads
0.52 probability of coming up tails.
coin is flipped 7 times
let's assume n = 7.
The seven flips of the coin are separate from one another, so what happens on one flip is unaffected by the outcomes of the other tosses.
When calculating the likelihood that two events will occur simultaneously, we must multiply the probabilities of events 1 and 2, presuming that event 1 occurred.
Tosses never affect one another, so the "assuming event 1 happened" part is no longer necessary because it has no effect on the probability. As a result, we just need to multiply the chances for each toss. This supposition is essential. We would have needed to know exactly how tosses are dependent on one another if they were interdependent.
Typically, we would have [tex](n! /(r!)*(n - r)!)*p^r*(1-p)^(n-r)[/tex] is the probability of getting r heads out of n, without taking into account the order.
probability of getting exactly 4 heads r = 4.
out of 7 flipping n =7.
7!/(4!*3!) = 35
(0.48)^4 = 0.05308416
(0.52)^3 = 0.140608
35*0.05308416*0.140608 = 0.26124201492 = 0.26
so the probability of getting exactly 4 heads is 0.26.
To know more about probability here,
https://brainly.com/question/23800890
#SPJ4
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.