If it is important to detect a mean difference in score of one point with the probability of at least 0.90 , then the number of pairs that should be used is 10 .
What is a Probability ?
The term probability of an event is defined as ⇒ number of favorable outcomes / total number of outcomes .
It is given that ,
the probability is at least 0.90 ,
So , in the paired t test ,
testing mean paired difference is = 0
alpha = 0.05 , the assumed standard deviation of paired difference = 0.441
So the output is
Difference = 1 , Size = 5 power(probability) = 0.90 ,
So , the actual probability is = 0.95190
From the output above , the required sample size is n = 5 .
We observe that , under the given conditions the sample size is = 5 .
but the researcher considered 10 pairs ,
So , the sample size 10 is used for this study .
Therefore , 10 pairs should be used .
The given question is incomplete ,the complete question is
It is important to detect a mean difference in score of one point with a probability of at least 0.90. how many pairs should have been used ?
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