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: a rectangular plot of land adjacent to a river is to be divided into two equal plots as shown. if there are 3162 ft of fencing to enclose the plot, what dimensions will maximize the area?

Sagot :

Dimension of maximize area is, length = 1581 m and breadth = 790.5 m.

Given that a rectangular plot of land adjacent to a river is to be divided into two equal plots. And 3162 ft of fencing to enclose the plot.

Consider the length is L and breadth is B of the plot.

Therefore the perimeter = L + 2B = 3162

⇒ L = 3162 - 2B

We know that area is the product of length into breadth i.e,

Area = L × B

        = (3162 - 2B) × B

Area = 3162B - 2B²

The maximum of the quadratic expression is

ax² + bx + c is at s = [tex]\frac{-b}{2a}[/tex] if a < 0.

Now we will calculate maximum point of the equation,

B = [tex]\frac{-3162}{2(-2)}[/tex]

B = 790.5

Now we will find the value of length,

L = 3162 - 2B

  = 3162 - 2(790.5)

  = 3162 - 1581

L = 1581

Hence the length of the rectangular plot is 1581 m and bredth is 790.5 m.

Therefore the maximize area = 1581 × 790.5 =124978

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