Answered

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two carts having masses of 1.5 kg and 0.7kg are initially at rest. they are held together by a massless spring. the spring is compressed and when released the 1.5 kg cart moves to the left with a velocity of 7 m/s. what is the velocity and direction of the 0.7 kg cart?

Sagot :

The velocity and direction of the 0.7 kg cart when released = 15 m/s to the right.

Law of conservation of momentum

The law of conservation of momentum explains that if two objects collide, the magnitude of the decrease in momentum on one object will be equal to the magnitude of the increase in momentum on the other object. This means, the total momentum of the system of objects before the collision is always equal to the total momentum of the system of objects after the collision.

The law of conservation of momentum can be written as follows:

m₁v₁ + m₂v₂ = (m₁v₁)' + (m₂v₂)'

We have,

Mass of the first cart = 1.5 kg ⇒m₁

Mass of the second cart = 0.7 ⇒m₂

The velocity of the 1.5 kg cart = 7 m/s ⇒ v₁'

It moves to the left, so it negative ⇒ -7 m/s

The carts initially at rest, so v₁ = v₂ = 0

And,

(m₁ + m₂) v₂ = (m₁v₁)' + (m₂v₂)'

(1.5 + 0.7) (0) = (1.5) (-7) + (0.7) v₂'

0 = (-10.5) + 0.7 v₂'

0.7 v₂' = 10.5

v₂' = 15 m/s

And 15 m/s ⇒ it is positive, the direction is to the right.

Learn more about law of conservation of momentum here: https://brainly.com/question/22257396

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