in a single-slit experiment, the slit width is 190 times the wavelength of the light. part a what is the width (in mm) of the central maximum on a screen 1.4 m behind the slit?

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06-12-2022
Physics

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in a single-slit experiment, the slit width is 190 times the wavelength of the light. part a what is the width (in mm) of the central maximum on a screen 1.4 m behind the slit?

Sagot :

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faizahmihani faizahmihani · Answer 1 · 2022-12-09T01:42:34-05:00

The width (in mm) of the central maximum on a screen 1.4 m behind the slit = 0.014 mm.

Diffraction of light

Diffraction of light on a single slit will produce maximum interference from the slit if the path difference between the light coming is:

(2n+1) ½ λ

Maximum interference if the difference in the paths taken by light from adjacent slits is equal to an integer multiple times the wavelength or also an even number times the half wave.

To determine the width from the maximum center on the screen behind the slit. use the equation:

Ym = mλD/a

We have,

a = 190 λ

So,

Y₁ = (1)λ (1.4) / 190 λ

= 0.007 m

And, width of the central maximum can be determined as:

Wc = 2Y₁

= 2 (0.007)

= 0.014 mm

Learn more about diffraction of light here: https://brainly.com/question/15904391

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Diffraction of light

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