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22. two slits, each 0.80 mm wide, are 2.6 mm apart: when light is shone through them onto a screen how many interference maxima are there between the first diffraction minimum on the left side and the first diffraction minimum on the right side? a 1 b. 3 c.5 d. 7 e.9

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rafikiedu18

Option (D) is the correct answer

Given data:  width of each slit, a = 0.80 mm.        

distance between the slits, d = 2.6 mm

If the wavelength of light is \lambda then,

2.6 ) = 2 x (0.8) = 6.5 r=2x

x = 7 ( taking the next higher integer of 6.5)

The wavelength of a wave describes how lengthy the wave is. The distance from the "crest" (top) of 1 wave to the crest of the following wave is the wavelength.

Alternately, we can degree from the "trough" (bottom) of 1 wave to the trough of the subsequent wave and get the equal price for the wavelength.

SI unit of wavelength is metre . At the same time as measuring wavelength the multiples or fractions of a metre is also used. Extensively, exponential powers of 10 are used whilst wavelengths are of a huge assets.

Learn more about Wavelength here:- https://brainly.com/question/10728818

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