Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.
Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)
Ao = 58.2*10^-6m
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)
comparable to case two
Ao = 40.6*10^-6m
Learn more about tolerant here
https://brainly.com/question/3709413
#SPJ4
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.