A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.

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06-12-2022
Physics

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A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.

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jaspreetsharma jaspreetsharma · Answer 1 · 2022-12-08T23:52:38-05:00

Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.

Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.

9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)

Ao = 58.2*10^-6m

9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)

comparable to case two

Ao = 40.6*10^-6m

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