Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
The given trigonometric equations have the value tan x, -cot x.
Since the given trigonometric equations are: cos2x-cos4x/sin2x+sin4x and cos2x+cos4x/sin2x-sin4x. The problem is related to trigonometric Ratios, which are the ratios of the side of a right-angled triangle.Now for the equation (cos 2x - cos 4x )/(sin2x +sin4x)
since we know the formulas :
cos A + cos B = - sin (A+B)/2 sin(A-B)/2
sin A - sin B = sin( A+B)/2 cos (A-B)/2
so for the equation, we can
= (-sin 3x) sin ( -2x)/2)/( cos 3x cos x)
= sin 3x sin x/ (sin 3x) cos x
= tan x
for the second equation cos2x+cos4x/sin2x-sin4x
= cos 3x cosx/ cos3x sin(- x)
= - cot x
To know more about trigonometric equations refer to the link brainly.com/question/27821667
#SPJ4
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
