Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

in 2001, the united states produced 51 percent of its electricity in the amount of 1.878 x 10^12 kwh from coal fired power plants. taking the average thermal efficiency to be 34 percent, determine the amount of thermal energy rejected by the coal-fired power plants in the united states that year.

Sagot :

The amount of thermal energy rejected by the coal-fired power plants in the united states is [tex]3.646.10^{12} kWh[/tex].

What is thermal efficiency?

The ratio of the heat produced by a heat engine to the total heat units in the fuel consumed that's what is meant by thermal efficiency .

[tex]nth=\frac{Wcoal}{Qin}\\nth=\frac{Wcoal}{Qout-Wcoal} 23\\Qout=\frac{Wcoal}{nth} -Wcoal[/tex]

[tex]Qout=\frac{Wcoal}{nth} -Wcoal\\Qout=\frac{1.878.10^{12} }{0.34} -1.878.10^{12}\\=3.646.10^{12} kWh[/tex]

Therefore, the amount of thermal energy rejected by the coal-fired power plants in the united states is [tex]3.646.10^{12} kWh[/tex].

To learn more about thermal efficiency from the given link.

https://brainly.com/question/14287776

#SPJ4

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.