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basilisk lizards can run across the top of a water surface (fig. 9-52). with each step, a lizard first slaps its foot against the water and then pushes it down into the water rapidly enough to form an air cavity around the top of the foot. to avoid having to pull the foot back up against water drag in order to complete the step, the lizard withdraws the foot before the water can flow into the air cavity. if the lizard is not to sink, the average upward impulse on the lizard during this full action of slap, downward push, and withdrawal must match the downward impulse due to the gravitational force. suppose the mass of a basilisk lizard is 90.0 g, the mass of each foot is 2.53 g, the speed of a foot as it slaps the water is 1.08 m/s, and the time for a single step is 0.417 s. (a) what is the magnitude of the impulse on the lizard during the slap? (assume this impulse is directly upward.) (b) during the 0.417 s duration of a step, what is the downward impulse on the lizard due to the gravitational force? (clearly the push, not the slap, provides the primary support for the lizard.)

Sagot :

The magnitude of impulse acting directly upwards during the slap is -0.00273 N.s.

The magnitude of the impulse that is downward on the lizard due to the gravitational force is 0.375 kg.m/s.

Given that, mass of the basilisk lizard = 90 g = 90/1000 kg = 0.09 kg

Mass of each foot = 2.53 g = 0.00253 kg

Vf = 0

Vi = 1.08 m/s

Time taken for a single step is 0.417 s

I = Δp = Mf * (Vf - Vi ) = 0.00253* (0 - 1.08) = -0.00273 N.s

On each step, the basilisk lizard must provide an upward force that counters its weight which is equal to W= mg.

We know the formula for impulse acting downwards is, I = F Δt

It can also be written as I = W Δt = Ml* g Δt

Substituting the values in the above formula,

Ml*g Δt = 0.09* 10* 0.417 = 0.375 kgm/s

To know more about impulse:

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