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4. if the rate constant for some reaction at 25 oc is 10 s-1, and if the arrhenius activation energy is 60 kj/mol, what rate constant is expected at 37 oc?

Sagot :

The rate constant expected at 37 °C when the rate constant for some reaction at 25 oc is 10 s-1, and if the arrhenius activation energy is 60 kj/mol  is 5.39 s⁻¹

The Arrhenius equation can be used to calculate the rate constant of a reaction at a given temperature given the rate constant and activation energy at a reference temperature. The Arrhenius equation is given by:

k(T) = k(T₀) * e^(-Ea/RT)

Where k(T) is the rate constant at the desired temperature, k(T₀) is the rate constant at the reference temperature, Ea is the activation energy, R is the universal gas constant (8.314 J/molK) and T is the temperature in Kelvin.

To calculate the rate constant at 37 °C, we can plug in the values for k(T₀) and Ea:

k(37°C) = 10 s⁻¹ * e^(-(60 kJ/mol) / (8.314 J/molK * 310 K))

k(37°C) = 10 s⁻¹ * 0.539

k(37°C) = 5.39 s⁻¹

Therefore, the rate constant at 37 °C is 5.39 s⁻¹.

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